Initialization of I2C communication between ADV7613 and STM32

Hi,

    Please let us know, Is there any intention for left shifting the IO map address (98<<1) ?

Thanks,

Poornima

Hi,

In I2C communication the first seven bits of the "address byte" contains the slave address, whereas the last bit is a read/write bit. 0 is write and 1 is read. The target device 7 bits address value must be shifted to the left before calling the HAL_I2C_Master_Transmit API. I understand that ADV7613_PRIM_MODE_ADDR and ADV7613_PRIM_MODE_DATA should be uint8_t data type. Below are the details of API:

/**
* @brief Transmits in master mode an amount of data in blocking mode.
* @param hi2c Pointer to a I2C_HandleTypeDef structure that contains
* the configuration information for the specified I2C.
* @param DevAddress Target device address: The device 7 bits address value
* in datasheet must be shifted to the left before calling the interface
* @param pData Pointer to data buffer
* @param Size Amount of data to be sent
* @param Timeout Timeout duration
* @retval HAL status
*/
HAL_StatusTypeDef HAL_I2C_Master_Transmit(I2C_HandleTypeDef *hi2c, uint16_t DevAddress, uint8_t *pData,
uint16_t Size, uint32_t Timeout)

Please let me know what is the correct way to access the target device ADV7613.

Regards,

Rupesh

Hi,

  Kindly note that, Our script use 8-bit addressing if incase your target device except 7 bit address you would need to right shift the 8-bit address by one to get into a 7-bit addressing.

 If your software/tool is using 7-bit I2C address, In that case, we need to right shift the 8 bit map address to one So you should use 0x4C to access the IO map address.