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Calculation for input noise of AD9649

Question asked by 朱煦然 on Jul 21, 2017
Latest reply on Jul 21, 2017 by DougI

I have found a formula from AN835 about the relationship between SNR and equivalent input noise,


about which I have two questions.

1. does the Noise represent 'rms' value or 'p-p' value?


2. why it would be divided by 2*sqrt2?


For AD9649, whose SNR=74.7 dbfs, input noise can be get from the formular,

Is that right?