I have found a formula from AN835 about the relationship between SNR and equivalent input noise,

about which I have two questions.

1. does the Noise represent 'rms' value or 'p-p' value?

2. why it would be divided by 2*sqrt2?

For AD9649, whose SNR=74.7 dbfs, input noise can be get from the formular,

Is that right?

Hi,

Thanks for your interest in AD9649.

I agree with your calculation using the formula.

Thank you.

Doug