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Linear sweep timing calculation in AD9954

Question asked by Nitesh.k on Apr 24, 2017
Latest reply on Apr 24, 2017 by KennyG


1. suppose i want to sweep AD9954 from 10 MHz to 20 MHz in step of 1 KHz (10000 steps). system clock freq is 400 MHz so sync clock will be 100 MHz(10 ns). if i keep ramp rate 10 ns then time require to complete the sweep is 10000* 10ns =100 us 

is this calulation correct??

2. is there any impact of faster and slower ramp rate on DDS performance (spur response, linearization.)??