Walt_Kester

December StudentZone Quiz Solution

Discussion created by Walt_Kester Employee on Dec 7, 2016

Solution:

From Kirchoff’s current law, the current through the 1k resistor is 5mA 2mA = 3mA. This 3mA current flows through the 1k resistor and creates a voltage of 3V at node B. The 2mA current flowing through the 2k resistor creates a drop across the resistor of 4V. The voltage at A is therefore 3V + 4V = +1V. The 5mA flowing through the 3k resistor creates a drop across the resistor of 15V. The voltage at C is therefore 3V 15V = 18V. The steps are labeled on the following diagram.

          

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