When I thought a current monitor circuit, I had a question about how to treat input offset voltage in differential amplifier.
For example, I draw a current monitor circuit with a differential amplifier of ADA4096 by ADIsimPE as the attached image.
When I1 = 0A, the output voltage is around 290 mV.
It seems to be so higher offset voltage than I expected.
My understanding is that the output voltage is 3.5mV x 10 = 35mV because I got VOS = 3.5 mV when R1 = 0, R6 = 100k, R2 = 100k.
Could you explain why the gain of the input offset voltage is 10 times higher than I expected?