AnsweredAssumed Answered

ADE7880 xWATTHR lower value

Question asked by rajam on Oct 25, 2016
Latest reply on Aug 21, 2017 by pminc48

Hello,

I am working with an ADE7880 and   set to 3-phase, 4 wire configuration.  I set to use the  Regular accumulation mode.

 

Here is the settings is 50Hz and 240, 100 meter

 

CT turns ratio = 1:5000 = 1/5000 = 0.0002

 

Burden = 13.2 ohms , ADE  fs  I/P(V) = 0.5 volt

 

Voltage divider = 1096k  = 1096000

 

Ifs = 0.5 fs *ct ratio/(R1+R2 x1.414) = 133.9 A

Like that  Ufs = 387.8 v

Vn = 240 v

Based on above value i calculate  VLEVEL = 6464134

WTHR = ?

 

Now i set WTHR = VARTHR = VATHR value = 0x03(default value)  like that

 

LCYCMODE = 0x40

 

CFxDEN

MC = 1600 and n= -3 (fixed it)  n - how calculate it ?

CFxDEN=  6250

COMPMODE = 0x3FF

I successfully get the Current, Voltage, V = 238.7 ,I = 2 ams  and But when PF  = 1     i Read watt value from reg. xWATTHR  = 535 and PF = 0.5 watt value xWATTHR= 170 like that is correct value?  Please help me ?

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