I catch 4 lines output of AD9680-500, the register of AD9680 is default.
First step is CGS, the output is BC(K28.5).Then ILAS, 4 multiframe start with 1C stop with 7C.Then data, four lanes is
lane0 cf459da1858f8182 582624314ec8221c ``````
lane1 f2f028280c0c0202 00fd7faaeacc2c22 ``````
lane2 cf459da1858f8182 582624314ec8221c ``````
lane3 f2f028280c0c0202 00fd7faaeacc2c22 ``````
lane2 and lane0 are same, lane3 and lane1 are same.
As shown in register 0x570,the default is 0x49,which meas number of lane is two, number of converter is two.
So the total rate of output should be 2*16*10/8*500Mbps=20Gbps ,10Gbps/lane.Why I can catch the output when the receiver is 5Gbps?
The second question is how the data represent the Vin.Does the data list above means Converter0 is cf45,9da1,858f,8182 and Converter1 is f2f0,2828,0c0c,0202?