Hello,

Is there any math to calculate the Phase at an image frequency using AD9958, let say in the region of 900 MHz obtained by 2*Fclock-Fc.

If the two channel at fundamental frequency (130 Mhz) have 50° phase offset what will be the phase offset at 2*Fclock-Fundamental

Thanks in advance for your support.

Regards

Hi, if the phase of the 130MHz fundamental is changed 50 degrees, the 900MHz image frequency would be changed by a scale factor of 900/130 or 6.92x. So, it would have a relative change of 6.92 * 50 = 346.15 degree change. Not sure what the initial phase would be between both signals. That would depend on the image used and also the band pass filter characteristics.