I have a question about the module "log2".
In our development, log10 module is needed.
Can I substitute some other module for the purpose? or is there any other way to accomplish it?
Thank you very much
Use a log identity: Logb x = Loga x/Loga b
log10(x)=log2(x)/log2(10). Or more efficiently, =log2(x) * (1/log2(10)), since it's a constant.
Thank you for your lecture!
I now remember the equation ever since I was 17 years old.
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