Recently， I bought AD8342-EVALZ-ND、AD9230-250EBZ-ND、ADRF6510-EVALZ-ND and HSC-ADC-EVALDZ-ND. I want to know how to connect them. In the homepage, balun transformer was written, can you give me an example? Thank you very much.
A couple of other comments:
I assume you will have the AD8342's output drive the ADRF6510, and in turn the ADRF6510 will drive the AD9230. I'm not familiar with the other 2 products, but I can help with the AD9230.
The AD9230 evaluation board is shared with the AD9434 family of products, and you can find the user guide here:
Figure 15 in this document has the schematic for the analog input to the PCB. I would suggest that you will have to remove resistors R104, R105, R108, and R109. Then you will need to connect the differential output of the ADRF6510 to R110 and R111. There are no connectors at these nodes, you will have to splice the boards together. I would normaly do this by sacrificing 2 cables. I'm not familiar with the ADRF6510, but I assume it's differential outputs are available at a coax connector. You can attach a cable with a connector to each output, and solder down the other end to the AD9230 evaluation board. The signal to R110 and R111, and the grounds to analog ground on the PCB.
I'll ask the applications support teams for the other 2 products to review this post as well.
If it were me, i would setup the interface between the AD8342 and the ADRF6510 as shown in Figure 45 in the AD8342 datasheet. Except i would change the 100 Ohm shunt resistor to 400 Ohms. That way, when combined with the ADRF650's 400 Ohm input impedance, the AD8342 would see 200 Ohms. And the ADRF6510's input would see 400 Ohms.
The 1.4V common-mode output voltage is a bit low for the ADRF6510. It would be good if this were set at 1.5V, if possible. The AD9230 still seems to have good SFDR at that slightly higher common-mode voltage.
Thank you very much
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