Section 4.3 in the hardware manual states that the input data can be right, center or evenly justified. But Table 16 only provides an example of 12-bit data (Input ID 0). I want to confirm it's possible to right justify RGB data so that R(7:0), G(7:0) and B(7:0) map to D(23:0). My confusion is that the alignment bit, 0x48 specifies it's for DDR alignment and 0x48 is the bit justification for YCbCr data. If it's possible to right justify 24-bits of RGB data what needs to be programmed?