AnsweredAssumed Answered

ADM3053 drive capability

Question asked by Terumasa on Jan 26, 2015
Latest reply on Jan 26, 2015 by Terumasa



Our customer will use ADM3053 and ask minimum combined impedance and drive capability.


I think below. ( in the case of  cable loss =0)

Is my understanding correct ?


Datasheet P.1 says "Connect 110 or more nodes on the bus".

If load of CAN bus is compesed of 110 nodes of ADM3054 in parallel ( 20Kohm minimum Differential Input Resistance of ADM2053),

Combined resistor is 180 ohm.

When this 180ohm  is in parallele with !20 ohm termination resistor*2  on the CAN bus, final combined resistor is 45 ohm.

So, minimum impedance will be 45 ohm and drive capability is driver output voltage(MAX) /combined resistor  =   3.0V/45 ohm =67mA.


If there is any wrong with my understanding, please let me know your advice.