I would like to know whether I can feed BPSK modulated date to AD9122 DAC in FCOMMS1?
Then what will be the Q channel data?
Your signal will not be complete with just I or just Q, you need both, they are different components of the same signal. If your BPSK block only outputs -1 and 1 you need to do a mapping of these numbers to two vectors in the complex plane which are 180 degree to each other and use these vectors as your I and Q output. E.g. a simple mapping would be -1 = (I=-1, Q=0) and 1 = (I=1, Q=0). And this is what you feed to the DAC. Make sure you do apply proper scaling to the signal.
For the first question, the short answer is yes.
I do not understand the second question. Your BPSK modulator should have an I and a Q output, which would feed the two channel of the DAC. Elaborate this question, if you thought of something else.
For BPSK modulator,i know have only one output,like +1 or -1.(continus)
The BPSK data would feed the one channel of DAC.
Why do you say have an I and a Q output for BPSK?
For some reason I thought that BPSK is a quadrature modulation, and it is not. Thank you for correcting me, and sorry for the misleading.
Thanks for your information.
you say some reason, can you tell me that reason?or recommend some webside.
FMCOMMS1 BPSK demodulation:
The BPSK signal input rx of S1.
BPSK Signal path is ADL 5380,AD8366,and AD9643.
For FPGA chip,it receive I and Q from AD9643.
How demodulate BPSK signal from I or Q?
You can find a lot of documentation on the internet, about Phase Shift Keying, I don't want to pull out any of it specifically.
If your modulator is 'connected', like Lars said in the answer above, you need to feed your demodulator just with the digitized I signal, and you should be fine. (Presuming that the modulator and demodulator using the same data mapping)
The BPSK modulator output have only I channel, right? Then how can I feed I and Q data inputs to DAC?
In the functional block diagram of AD9122 PCORE 2 DDS are shown. DDS-1a for generating I1, DDS-1b for I2, DDS -2a for Q1, DDS -2b for Q2. Then I1 + I2 giving I data and Q1 + Q2 giving Q data. In the case of DBPSK modulation what will be this I1,I2,Q1 and Q2?
Thank you Lars
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