Please teach me about AD5662.
Vout=Vref * (D/65,536)
In this value, what gain is output buffer amplifier?
I think that the gain=2 when Vfb pin is connected with Vout pin.
Which is the output in that case 0- Vref or 0-2Vref ?
The reference is internally divided by two and later amplified by the output buffer.
Consequently, Vout = Vref * D / 65536
the inverting pin terminal is offered to remotely sense the output voltage and compensate any voltage drops for example in a long cable.
Let me know if something is not clear, please
Thanks your reply.
Please let me clarify it.
Is the case where resistance is not put between Vfb pin and Vout pin the following expression?
Vout = Vref * D / 65536
Do it become the gain of the above-mentioned expression when the following doesn't put resistance between Vfb pin and Vout pin?
Can anyone make a response?
Apologies for the delayed response.
When the Vfb pin and the Vout pin is shorted (meaning no resistance is connected in between), the equation below applies.
Please let us know if you have any further questions.
My question became clear.
Thanks so mach.
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