We are studying about your AD9280 8bit ADC.
I have a question.
We need the input-impedance for our simulation.
Impedance =Fs voltage / DC leakage current, we think, correct?
On your datasheet show DC leakage current =43uA when Fs=32MHz max.
Impedance mean 32MHz/43uA.
Our Fs(sampling freq (Conversion Rate)) is 2MHz.
So what is the DC leakage current Fs=2MHz?
Otherwise how should we think your input-impedance for this case?