For AD7764 Status Register Read Cycle, it is described on page 21 of Data Sheet as below.
"To ensure that the next read cycle contains the contents of the register written to, the write operation to that register must be completed a minimum of 8 × t SCO before the falling edge of FSO which indicates the start of the next read cycle. "
But if the time is less than 7×tSCO, how becomes the behavior of SDO?
1. The next read out is conversion result, then the next read out is the contents of the register.
2. The contents of the register is not output.
3. Other behavior.