Hi friends,

I am using ADE7763.

as far as now i am finished with Volt, Current, KWh, KVAh ,Frequency and instantaneous KVA (i.e. V * I)

my question is.

how do i find instantaneous Active Power i.e. KW and PF.

according to power triangle.

i thought PF can be calculated as

PF = KW**H** / KVA**H** by considering LINECYC register.

but it seems to be not right.

can any one suggest me. how to compute KW and PF.

Regards,

Umesh

Hi Umesh

By using the WSMP bit of the Interrupt Enable register and MODE register, you can get the sampled waveform data of instantaneous active power in the WAVEFORM register.

And for the Power Factor, Active Power/ Apparent Power would give the magnitude of the power factor correctly. For the sign, use the sign of the reactive power. If the result doesn't make sense, kindly reply back with an example result that you get and the input conditions pertaining to it.

Regards

hmani