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Output Noise Conversion

Question asked by EricM on Sep 7, 2012
Latest reply on Sep 11, 2012 by EricM

I would like to know how to convert correctly dBc/Hz to pA/sqrt(Hz). The AD9744 is 50 pA/sqrt(Hz) for IOUTFS = 20 mA and the AD9707 is -161  dBc/Hz for IOUTFS = 5 mA and Fc = 175 MHz / Fout = 6 MHz, so what is the difference for the output noise current?

 

Regards,

Eric

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