I have a question concerning the Datasheet of the AD8333. The transconductance gain on page 3 is calculated as Iout/Vin. As Vin is an AC-signal, which voltage is taken for Vin? Is it Vrms or Vpeak?
The designer used an rms based approach to determine transcanductance.
Thanks for the question!
Moving this thread to the Amplifier Community
Transconductance gain value isn't affected by the format of the units, thus as long as the format and conditions were used the gain gain will not change. That being said, if you need more detail I can check to see if the designer can shed more light on the question. (The transconductance gain was provided by the designer, format wasn't specified).
Thanks for your reply so far. I would appreciate if you could clarify this question with the designer
OK. will do.
I would just add a little more information which might be helpful. The transconductance is simply the output current divided by the input voltage. You'll note that the input format to the device is voltage, the output is current. Whether the input or output unit convention is volts-peak or volts rms is immaterial.
The designer is not at this ADI location so please allow time for communication and local conditions.
Lastly, I was just wondering about the background of the question, are youo thinking the peak vs. rms would make a difference? Is the question in regards to an existing application, proposed application, something else?
Well, the point is, that the AD8333 is a Mixer, so the input is in our case a 15MHz sinewave with a given amplitude, which will be down-converted with the same 15MHz-signal. So the output hence is a DC-signal proportional to the input sinewave signal. Now the question is, is the DC-output correspondig to the AC-Input RMS or Peak when calculating with transconductance?
Got it, thanks much!!
That's great news! Thanks for your help, I really appreciate that.
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