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How to set the control-register of the AD7923 correctly?

Question asked by marc.schueller on May 21, 2012
Latest reply on May 21, 2012 by JimmyC

Hello everybody,

 

the control-register of the above mentioned ADC is 12-bit wide. I suggest that two bytes have to be send via DIN. As only the first 12 bytes are "important" I have filled up the remaining bits with zeros.

I want to use the ADC the following way:

- using sequencer function

- scan all four channels (channel 0 up to channel 3)

- no shutdown-mode

- use small range

- use binary coding

 

Therefore the bytes I send to the control-register are: CF 90 hex where CF is the first byte and 90 is the second one.

binary representation (with delimiters)

1 1 0 0 | 1 1 1 1 | 1 0 0 1 | 0 0 0 0

 

Altough I tought that I use the sequencer function I only get results from channel 1.

What I am doing wrong?

 

Best regards.

[Marc Schüller]

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