AnsweredAssumed Answered

7612 manually generated interrupt

Question asked by rqiu@qualcomm.com on Apr 26, 2012
Latest reply on Apr 30, 2012 by mattp

Hello experts,

 

I am trying to use MPU_STIM_INTRQ to manually generate interrupt for debugging porpuse. However, I found it can only fire once just after 7612 initialization.  Thereafter, writing MPU_STIM_INTRQ is not effective.

 

Here is my pseudo codes for triggering the interrupt

 

write 98 4B 80

write 98 40 e6

read 98 47 2

write 98 49 80

 

Thank you in advance for your help

 

Robert

Outcomes