hi,there!

I follow the datasheet to calculate the CRC of channel,but I can not get the value same as the ADC's.

here is the four samples:

B507BD

94F6F2

D39BC9

395ED1

the CRC from the ADC is C8.

I use the tools from http://www.analog.com/media/en/engineering-tools/design-tools/AD7779-CRC-Calculator.zip ,the result is right.

But please help me with the MATLAB to get the right result.

here is the code:

p=[1 0 0 0 0 0 1 1 1]';

a=reshape(de2bi(data16(1,1:4),24,'left-msb')',96,1);

a=[a' 1 1 1 1 1 1 1 1]';

[m n]=size(a);

kkk = 9;

b = a(kkk-8:kkk,1);

while ((m-kkk)>0 )

if( b(1,1) == 1)

b = bitxor(b,p);

end

while ( (b(1,1) == 0)&&(kkk < m) )

kkk = kkk + 1;

b =[b(2:end,1)' a(kkk,1)]';

end

end

if( b(1,1) == 1)

crcchk = bitxor(b,p);

else

crcchk = b;

end

crcchk = crcchk(2:9,1)

Thanks for your help.

Hi,Thanks for your email.

Before this,I read another blog AD7779 CRC calculation for AD7779. It seems to be the same problem,and following the article I can get the right result. I thinks the datasheet of AD7768 about the CRC calculation is not right.