Hi Sir,
I haven't seen the reference circuit in the data sheet,could you give me a sample?
Thanks,
Zepeng.
ADG839
Production
The ADG839 is a low voltage CMOS device containing a single-pole, double-throw (SPDT) switch. This device offers ultralow on resistance of less than 0...
Datasheet
ADG839 on Analog.com
Hi Sir,
I haven't seen the reference circuit in the data sheet,could you give me a sample?
Thanks,
Zepeng.
EricC - Moved from Power Management to Switches/Multiplexers. Post date updated from Tuesday, November 26, 2024 7:02 AM UTC to Wednesday, November 27, 2024 10:59 AM UTC to reflect the move.
Hi 1111111112 ,
Could you please clarify if you need an application circuit use case, a schematic sample, or if an application circuit of a similar product would suffice?
Regards,
Gelo
Hi Gelo,
Thanks for your replying.I need an application circuit case,I would like to know the circuit capacitance values and resistance values.
Thanks,
Zepeng
Hi 1111111112 ,
Thank you for your reply. To provide you with the most accurate application circuit, could you please specify your target application? This will help me tailor the circuit to your needs.
In the meantime, you can refer to the LTspice model example circuit for simulation purposes. If you are looking for specific values such as on resistance and source/ drain capacitance, these details are available in the datasheet. I have included a snippet of this information below for your convenience.


Please let me know how you would like to proceed.
Regards,
Gelo
Hi Gelo,
Thanks for your reply.I would like to use STM32 as input to choose when is S1 on or when is S2 on.This is my schematic design. Could you tell me what capacitance value I should pick for?
Thanks,
Zepeng
Hi 1111111112 ,
Thanks for your reply. I understand that you would like to use the STM32 to control when S1 or S2 is on. Based on your schematic design, where C10 is in series with the Vdd pin and the 3.3V source, and R19 is in series with the IN pin and ground, I recommend the following:
Additionally, while you are sending a signal to S2, the IN pin is referenced to ground through R19. This means the switch will connect the COM pin to the NC (normally closed) pin, which is S1. Therefore, the output will actually be the signal from S1.
Regards,
Gelo
Hi Gelo,
Thanks for your reply. Excepet the Vdd pin and the IN pin,does other pins need capacitor or resistor to connect?
Thanks,
Zepeng
Hi 1111111112 ,
Please see the attached image below as well as the notes I wrote in it.

This circuit is a modified version of yours based on my understanding, ensuring a typical setup without requiring additional resistors or capacitors on other pins.
However, the (D) or (OUT) pin can be connected to a resistive or capacitive load of your choice.
Regards,
Gelo
Hi Gelo,
Thanks for your reply.I've solved my problem.I'm very appreciated for your help.Wish you have a good day!
Thanks,
Zepeng