• RE: AD8561单+5V供电，方波输入，输出延时问题

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    Thank you,
    …

  • RE: Using AD8561 for 100kHz or higher frequency Sine to Square Wave Conversion (zero crossing detector)

    This question has been assumed as answered either offline via email or with a multi-part answer. This question has now been closed out. If you have an inquiry related to this topic please post a new question in the applicable product forum.

    Thank you,
    …

  • 关于IC型号AD8561后缀问题

    关于IC型号AD8561后缀问题，我想要知道图中两个芯片（AD8561）的后缀是否一样？

    谢谢！

  • 用AD8561对输入尖峰脉冲整形输出波形异常问题求解？

    由于传感器输出的尖峰波形宽度很窄，不是标准的波形信号，因此用高速比较器将该信号整形处理成标准方波，方便后端计数单元处理，问题是：用高速比较器整形的波形不是理想的方波，而是输出一个幅度变化的尖峰波形，初步怀疑是比较器的相应时间不够，但是没有充分足够的理由支持,希望ADI的技术出来解答下啊!

    • attachments.zip

  • AD8561比较器的问题

    使用AD8561作为比较器芯片,可是电路工作时,输入参考信号出现了较大的尖锋干扰电压,请问这是怎么回事呢?这个是电路.

  • How can i improve the rising time and falling time of AD8561?

    My aim is that the input varies between 0 to 5 volts with 500 Hz (like amplified and rectified EMG signal) and the reference is for example is 2 volt. If the input is bigger than referance the output must be 5V, for the opposite status the output must…

  • RE: Can i use +7v supply for AD8561 to generate +5v output with 8ma load?

    Hi Arpit,

    Can you clarify whether your question is on the AD8561 (as in the title) or AD584?

    With regard to the AD584, based on the datasheet, yes, you do need 2.5V headroom from output to supply.

    Thanks!

    Kris

  • AD8611: Jitter add to the signal

    Q 

    I am choosing a comparator for a clock recovery (frequency about 5...20 MHz); I
    liked the Analog Devices's AD8611 and AD8561 specifications, but I would really
    appreciate any information about the jitter additions I could expect if I
    choose…

  • Input parameter measurement for a comparator

    How to measure he CMRR, offset current, bias current and offset voltage of AD8561 Comparator? Can you elaborate on the test circuits and test methods to test these parameters.?

  • RE: HMC704 input reference frequency

    Yes, I agree according to your equation if you have two choices with identical N multiples:

    1. 1MHz to 100MHz
    2. 10MHz to 1GHz

    Pick the lower frequency option, or in other words the lower Fpfd,  for best phase noise.

    For a given output frequency…