由于传感器输出的尖峰波形宽度很窄,不是标准的波形信号,因此用高速比较器将该信号整形处理成标准方波,方便后端计数单元处理,问题是:用高速比较器整形的波形不是理想的方波,而是输出一个幅度变化的尖峰波形,初步怀疑是比较器的相应时间不够,但是没有充分足够的理由支持,希望ADI的技术出来解答下啊!
My aim is that the input varies between 0 to 5 volts with 500 Hz (like amplified and rectified EMG signal) and the reference is for example is 2 volt. If the input is bigger than referance the output must be 5V, for the opposite status the output must…
Hi Arpit,
Can you clarify whether your question is on the AD8561 (as in the title) or AD584?
With regard to the AD584, based on the datasheet, yes, you do need 2.5V headroom from output to supply.
Thanks!
Kris
How to measure he CMRR, offset current, bias current and offset voltage of AD8561 Comparator? Can you elaborate on the test circuits and test methods to test these parameters.?
Yes, I agree according to your equation if you have two choices with identical N multiples:
Pick the lower frequency option, or in other words the lower Fpfd, for best phase noise.
For a given output frequency…
Hi nemislatmos,
Our space-qualified products follow a standard naming configuration: partnameS. (e.g. AD8561 space-qualified equivalent is AD8561S)
We do not have ADA8561 in our portfolio. Did you mean AD8561? As mentioned, the space-qualified equivalent…