• ### AD633 Input Offset Problem

1. As AM Modulator per data sheet

2. Signal into Y1 is 1000Hz sine at 2V p-p (via 10uF cap)

3. Signal into Z is connected to Y1

4. Signal into X1 100Hz sine at 8V p-p (via 10UuF cap)

5. Y2 and X2 are grounded

6. Supply voltage…

一.

这是输入的两个信号，最上面一个作为被除信号，下面一个作为除信号。

这是通过除法器后的信号，其中最上一个信号是被除信号，下一个为除法器输出信号（结果），我认为在被除信号处于正半周的时候，输出结果没有什么问题（不考虑过零点），但是在负半周的时候，我认为应该是一个接近于3V的直线（取被除信号负半周峰值为0.4V,除数信号负半周峰值为1.2V）,结果

与我预期的不符合，求高手解惑。

• ### AD633 error on LTSPICE

I want to use AD633 as a squaring IC for my circuit. The problem is that when i want to simulate it on LTSpice sofware, it gives me error

Analysis: Time step too small .........

• ### Sawtooth to AD633 for multiplication

i have a sawtooth  at f ~=40 kHz and Vp=1V  created with 555 timer lets call the output as X and i want to do X*X.
So i use AD633 multiplier but does not work with my sawtooth.Multisim throughs convergence error.Now the weird part...The multiplier works for…

• ### AD633 total scale factor error

The datasheet shows a max of 3% total scale factor error.  Since the devices output is ±10v is the error full scale of 10v or 20v?

Thanks,

-John

### Q

The transfer funciton with +-15V power supply is W=(x*Y)/10 +Z - Is the
transfer function unaffected when operating with +-8V power supply ? e.g X=3V,
Y=3V resulting in W=0.9V.  What happens if the device is operated with
unsymmetrical…

输入为1k和5k的信号，参考回路为1k信号，有效值为1V，后面带通滤波器中心频率1k，低通截止频率为100Hz。但是输出为什么是10Hz的信号，如下图所示

• ### Problem with AD633 Square Rooting

Hi everybody,

I have a problem with the AD633AZR: I have a 2V offset in the output, which is intolerable for my application (active anti-noise system).

I have build my circuit with the Figure 15 Page 9 of the datasheet Rev. K.

Here is the datasheet…