• AD633 Input Offset Problem

    Simple AD633 circuit.

    1. As AM Modulator per data sheet

    2. Signal into Y1 is 1000Hz sine at 2V p-p (via 10uF cap)

    3. Signal into Z is connected to Y1

    4. Signal into X1 100Hz sine at 8V p-p (via 10UuF cap)

    5. Y2 and X2 are grounded

    6. Supply voltage…

  • AD633除法电路

    使用AD633与AD711按照官方提供的电路搭建了一个除法器,在使用中发现与实际不符,求解答

    一.

        这是输入的两个信号,最上面一个作为被除信号,下面一个作为除信号。

        这是通过除法器后的信号,其中最上一个信号是被除信号,下一个为除法器输出信号(结果),我认为在被除信号处于正半周的时候,输出结果没有什么问题(不考虑过零点),但是在负半周的时候,我认为应该是一个接近于3V的直线(取被除信号负半周峰值为0.4V,除数信号负半周峰值为1.2V),结果

    与我预期的不符合,求高手解惑。

  • AD633 error on LTSPICE

    I want to use AD633 as a squaring IC for my circuit. The problem is that when i want to simulate it on LTSpice sofware, it gives me error

    Analysis: Time step too small .........

    I have read about this problem on diffrerent forums and had adopted those…

  • Sawtooth to AD633 for multiplication

    i have a sawtooth  at f ~=40 kHz and Vp=1V  created with 555 timer lets call the output as X and i want to do X*X.
    So i use AD633 multiplier but does not work with my sawtooth.Multisim throughs convergence error.Now the weird part...The multiplier works for…

  • AD633 total scale factor error

    The datasheet shows a max of 3% total scale factor error.  Since the devices output is ±10v is the error full scale of 10v or 20v?

    Thanks,

    -John

  • AD633: Operates with unsymmetrical power supply

    The transfer funciton with +-15V power supply is W=(x*Y)/10 +Z - Is the
    transfer function unaffected when operating with +-8V power supply ? e.g X=3V,
    Y=3V resulting in W=0.9V.  What happens if the device is operated with
    unsymmetrical…
  • 关于AD633的仿真

    最近在用AD633做仿真电路图如下所示

    输入为1k和5k的信号,参考回路为1k信号,有效值为1V,后面带通滤波器中心频率1k,低通截止频率为100Hz。但是输出为什么是10Hz的信号,如下图所示

  • Problem with AD633 Square Rooting

    Hi everybody,

    I have a problem with the AD633AZR: I have a 2V offset in the output, which is intolerable for my application (active anti-noise system).

    I have build my circuit with the Figure 15 Page 9 of the datasheet Rev. K.

    Here is the datasheet…

  • AD633与AD734能否兼容

    AD633替换AD734后无法输出

     DOC PDF

  • 关于AD633的使用疑问

    目前我们想将超声波信号转换成人耳能听到的声音,想用AD633作为混频器使用,目前我们超声信号的频率为40Khz左右,另外想用有源晶振产生32.768Khz的信号,这样两个信号输入到AD633,在通过一个截止频率为10kz的低通滤波器滤出两个信号的差频信号,然后在通过一个音频放大器驱动耳机,不知道这样是否可行,如果可行在使用的时候有没有什么需要特别注意的地方。另个个人感觉这个方案的成本有点高,不知道除了这个方法还有没有什么更好的方案,谢谢了。。。。。。