In order to use DPD (digital pre-distortion), we need to have in the TX chain a bandwidth 5 times the bandwidth of the usefull signal.
Considering LTE BW = 5 MHz, we need at least a BW = 25 MHz for the TX chain, but only 5 MHz in the RX chain.
Is it possible to set AD 9361 to work in these conditions? (BW TX = 25 MHz, BW RX = 5 MHz) ?
In this case, what will be the sampling rate needed?
Will the sampling rate be the same for RX and TX or is it possible to set it independently for ADC and DAC?
Thanks.
You can configure Rx and Tx for different bandwidths.
Please see this post for an answer on data rates:
Re: Is it possible to have different data rates on Tx and Rx?
Thanks.
I saw the post (Re: Is it possible to have different data rates on Tx and Rx?) but there it is shown that we can only set RX_data_rate = N x TX_data_rate, where N = 1 or 2. Let´s assume we make N = 1.
Today I have a reference design running for BW = 5 MHz (TX and RX), so we will need to increase TX data rate 5 time, or TX_data_rate = 5 x TX_data_rate_reference_design for TX BW = 25 MHz.
Because RX BW is still 5 MHz, and TX BW = 25 MHz, I will be oversampling the RX.
My question is: is there any side effect or drawbacks of this oversampling on the AD 9361 RX digital filter design?
Is it possible to redesign and get the same RX filter response I already have if I make RX_data_rate 5 time the current value?
Main drawback will be increased power consumption. If you will be using CMOS for the digital interface you may see more noise and spurious.
You can use AD9361 Filter Design Wizard to design the desired filter response.