What will be the attenuation at 24MHz if MAX2112 is programmed at 4MHz cut off?

MAX2112 is a 7 th order low pass filter, so the roll-off is at the rate of 7*20 = 140 dB/decade. The attenuation at f2 relative to f1 (f2 > f1) in dB will be given by: A = 140 log 10 (f2/f1) So, if the cut off frequency is 4MHz, the attenuation at 24MHz would be 109dB.

How to find the I2C Read and Write slave addresses in MAX2112? The information in datasheet is not clear enough.

The MAX2112 has a 7-bit slave address that must be sent to the device following a START condition to initiate communication. The slave address is internally programmed to 1100 000 The write/read address is C0/C1 if ADDR pin is connected to ground. The write/read address is C2/C3 if ADDR pin is connected to VCC. The first 6 bits of the address are fixed (1100 00) while the seventh bit can be 0 or 1 depending upon if ADD is connected to GND or Vcc as follows ADD pin is connected to GND The 7 bit slave address will be 1100 000 so a RD address will be 1100 0000 = 0xC0 similarly a WT address will be 1100 0001 = 0 xC1 ADD pin is connected to Vcc The 7 bit slave address will be 1100 001 so a RD address will be 1100 0010 = 0xC2 similarly a WT address will be 1100 0011 = 0xC3