AD8302 input signals

Hi,

If i want to inject -30 dBm, then i need to refer to a level of -43 dBV according to page 17, knowing that 1Vrms = 20 log (1) in dBV. From this, i should inject a voltage of 10 ^ (- 43/20) which will finally gives me 7.07 mV in the end to reach my  -30dBm. According to this result, i want to know if i have to send 10mV peak value or 7.07 mV peak value from my signal generator ?

Also, when i'am reading the mag and phase with no inputs, i should read something around 900mV, but i'am reading instead around 450mV ?

regards

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  • +1
    •  Analog Employees 
    on Aug 9, 2019 2:39 PM

    The answer is already in your stated Vrms to dBV relationship.  Let me restate the dBV definition for more clarity. 

    Number_in_dBV = 20*log10(Number_in_Vrms/1Vrms)

    Number_in_Vrms = 10^(Number_in_dBV/20) * 1Vrms

    -43 dBV translates to 7 mVrms, which is 10 mVp.

Reply
  • +1
    •  Analog Employees 
    on Aug 9, 2019 2:39 PM

    The answer is already in your stated Vrms to dBV relationship.  Let me restate the dBV definition for more clarity. 

    Number_in_dBV = 20*log10(Number_in_Vrms/1Vrms)

    Number_in_Vrms = 10^(Number_in_dBV/20) * 1Vrms

    -43 dBV translates to 7 mVrms, which is 10 mVp.

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