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ADG5421 Recommended for New Designs
The ADG5421 is a monolithic industrial CMOS analog switch containing two independent latch-up immune single-pole/single-throw (SPST) switches. Each switch...
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CN0540/DE10-nano signal wrong

fireire233

on Feb 22, 2023

Category: Hardware

Product Number: CN0540/DE10-nano

Hi,

I use the cn0540 with de10-nano to connect data below. The DS1(Power), DS2(fault) and DS4(CC) are on.

I connect the vibrating IEPE sensor to SMA or connect signal source with voltage amplitude of 1V to VIN (P10 disconnected). However, with the help of iio-oscilloscope, the plot seems that the board only has noise and can not collect the sensor data.

I tentatively infer that there are some error in switch ADG5421 and test the connection and disconnection of some nodes.

According to schematic diagram below, i find R61 left node is not connected to R10 up node but R61 right node is connected to R10 up node. So i infer that ADG5421 is broken. Is it right?

0 rogueC

over 1 year ago
Hi fireire233,

When the input channel is enabled in iio oscilloscope, what is the DC voltage in VIN? For IEPE signals this should be at around 10V to 13V.
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0 fireire233
over 1 year ago in reply to rogueC
The DC voltage in VIN(left R61) is aroud zero whatever the IEPE sensor is connect when the input channel is enabled in iio oscilloscope
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0 rogueC

over 1 year ago in reply to fireire233
Can you also check the value of VDD for ADG5421? And also check the logic levels of SW_CC and SW_IN?
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0 fireire233
over 1 year ago in reply to rogueC
I check the value of VDD for ADG5421, it is about 25.7V. I also check the logic levels of SW_CC and SW_IN, they are both high(3.3V).
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0 FormerMember

over 1 year ago in reply to fireire233

It sounds like your sensor isn't getting powered, since on an IEPE line that power comes from the onboard current source of the CN0540. Can you ensure that P10 has the shunt connected?

The other thing to check would be logic level of the FF pin, if a fault is detected then the switch will automatically be open and no signals will pass through.