ADR127: Turn-on time when using a 0.1uF in parallel with a 10uF at its output?

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Q 
 How long is ADR127 turn-on time when using a 0.1uF in parallel with a 10uF at its output? I can see at the datasheet that for 0.1uF the turn-on time is about 80us but I don't have any clue on how much this time increases in the case of the increased output capacitanc. In my project the power supply is switched on/off by a hardware power switch. So, I would like to know how much time we should allow to pass from the time the supply voltage is applied until I am sure that the output of ADR127 is stable enough. 
 
 A 
 The bigger the capacitor, the longer it takes to get to final value. When the capacitor is totally discharged, it appears as a short, so you will get about 20-25 mA into the capacitor. As the capacitor voltage comes up, you will get less and less current. With a micropower reference, the internal loop bandwidth is not very high so that is another factor. What is "stable enough&rdquo; will depend on what the reference is used for, whether for an ADC, a reference trip level, etc, as to whether or not you need to get within 1% of final value, or 0.1%, etc. As a rough cut, with dV/dt = I/C &agrave;C*dV/I = dt or 10.1uF*1.25V/1mA = 12.6 ms. (1 mA is a reasonable average) You can look at one on the bench, see the time to a final voltage within your desired error band, and then double it for a safety margin over process and temperature variations. Also put a scope on your switch and look at switch bounce time. Every time you go back to zero volts, the part resets.

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ADR127: FAQ