LT3922 Buck Mode LED Driver

Hello LT Support,

 

 

I want to use the LT3922 in Buck Mode as an LED Driver for a 12V/1,5A LED (one power LED). The supply voltage is 15V. Additionally I want to use the SSFM option with up to 2MHz switching frequency (base fsw=1,6Mhz*125%).

 

The goal is to achive very low noise EMI on PCB Level.

 

Will this application be possible without any issues with the mentioned configuration?

In the datasheet there is an example application (added as attachment). What exactly does the Q1 pnp do? A detailed answer in connection with the functional sequence would be great  

 

Any advices, like which filter to add to the output/ input or which changes to apply to the example application are appreciated a lot. 

 

Thank you!
Max K.

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  • Sopmodtheo thank you for trying to assist maxka. We appreciate your willingness to help other members however, your approach is not the one I would have chosen. The ADI approved approach is to first, use the LT3932 for buck LED driver with low EMI.

    The demonstration circuit DC2286A already has EMI filters on it.

    The demonstration circuit DC2247A has LT3922 EMI filters on it if you want to use them. If you want to use LT3922 as buck mode, you can. The transistor is used as a level-shift for over voltage protection. The idea is that a voltage is developed across the LED string which pulls a certain current through the upper resistor in the level-shifter.

    That current goes through the collector and emitter of the transistor and creates a voltage from FB pin to GND. When the output voltage is too high (LED string is removed), the FB resistor goes to high voltage and the part recognized the open LED condition.

    There are two configurations of the level shifter. One has a resistor divider at the base, and one does not. The resistor divider is used at the base of the transistor only when very low dropout in buck mode is needed. When that is needed, the base resistor divider allows the level shifter to still create a high (1.2V) voltage at the FB pin when the LEDs are open. However, if low dropout is not needed (low VIN to high open LED voltage), then the FB pin will not get squished down during an open event and the divider is not needed.

    Still LT3932 is a better fit since buck LED driver with low EMI is more obvious solution here.

Reply
  • Sopmodtheo thank you for trying to assist maxka. We appreciate your willingness to help other members however, your approach is not the one I would have chosen. The ADI approved approach is to first, use the LT3932 for buck LED driver with low EMI.

    The demonstration circuit DC2286A already has EMI filters on it.

    The demonstration circuit DC2247A has LT3922 EMI filters on it if you want to use them. If you want to use LT3922 as buck mode, you can. The transistor is used as a level-shift for over voltage protection. The idea is that a voltage is developed across the LED string which pulls a certain current through the upper resistor in the level-shifter.

    That current goes through the collector and emitter of the transistor and creates a voltage from FB pin to GND. When the output voltage is too high (LED string is removed), the FB resistor goes to high voltage and the part recognized the open LED condition.

    There are two configurations of the level shifter. One has a resistor divider at the base, and one does not. The resistor divider is used at the base of the transistor only when very low dropout in buck mode is needed. When that is needed, the base resistor divider allows the level shifter to still create a high (1.2V) voltage at the FB pin when the LEDs are open. However, if low dropout is not needed (low VIN to high open LED voltage), then the FB pin will not get squished down during an open event and the divider is not needed.

    Still LT3932 is a better fit since buck LED driver with low EMI is more obvious solution here.

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