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Multiplier at INV input of the Current Error Amp

Thread Summary

The user inquired about the function of a 1.25 x (1-D) multiplier connected to the inverting input of the CURRENT ERROR AMP in a block diagram. The final answer explains that this multiplier is part of the internal equation to calculate output current based on the duty cycle and Vc voltage, pulling down Vc when the output current exceeds the current limit set by IREG.
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Category: Hardware
Product Number: LT8316

Hello,

In the block diagram on page 8 of the datasheet, there is a multiplier labeled "1.25 x (1-D)" connected to

the inverting input of the CURRENT ERROR AMP. Could you please explain the reason for this operation and the formula?

Thanks,

Parents
  • Hello Satoru-san,

     Thank you for your reply. I understand the (1-D) part of the formula, and I gather that the coefficient 1.25 is a value based on the internal equation.

     Thank you also for the additional explanation regarding the operation; that is very helpful. I apologize for the delay in getting back to you.

    Regards,

Reply
  • Hello Satoru-san,

     Thank you for your reply. I understand the (1-D) part of the formula, and I gather that the coefficient 1.25 is a value based on the internal equation.

     Thank you also for the additional explanation regarding the operation; that is very helpful. I apologize for the delay in getting back to you.

    Regards,

Children
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