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Dropout Voltage and Programmable Current Limit

Category: Hardware
Product Number: LT3045

The dropout voltage with an input voltage of 15V at ILOAD = 300 mA (300mV) and 500 mA(430mV) appears to be too high in our measurements. We measured Input und Output voltage and calculated the dropout voltage like that.

Circuit Design: (Rlim = 0ohm, 4,7uF on Input Voltage)

Additionally, we would like clarification on the correct method for measuring the programmable current limit of the LT3045.

According to the datasheet, the current limit is specified with VIN = 2 V and VOUT = 0 V.
Our understanding is that the measurement should be performed as follows:

  1. Apply VIN = 2 V to the LT3045.
  2. Connect a load to the output.
  3. Increase the load current gradually.
  4. The point at which the output current stops increasing—while the output voltage begins to drop—should correspond to the current limit.

Could you please confirm whether this is the correct method for measuring the programmable current limit?

Thread Notes

  • Hello,

     

    The values you get for the dropout is aligned to the datasheet, please see page 3 under Dropout Voltage parameter. 

     

    Yes this is the correct way to measure and check the current limit. Another way is if you are using a resistor at ILIM pin, you can measure the voltage drop across which will be in the range of 0V to 300mV and calculate the equivalent current. This pin is also use for current monitoring, see datasheet page 20.

     

    Thanks.

  • Thank you for the information.
    I measured the dropout voltage as described in the Note 5 from the datasheet. However, the soft dropout voltage is still to high with 314mV for the 300mA Load and 429mV for the 500mA Load. 

    I measured it like that:

    • Set the desired load current (e.g., 300 mA or 500 mA).
    • Apply a sufficiently high input voltage so the LDO is fully regulating (e.g., 2–3 V above Vout).
    • Measure the regulated output voltage at this load → call this Vout_reg.
    • Calculate the 1% regulation limit:
      Vout_1%= 0.99×Vout_reg
    • Slowly reduce the input voltage (VIN) until the output drops to Vout_1%.
    • At that moment, record VIN → call it VIN_reg.
    • Dropout voltage = VIN_reg – Vout_1%.

      The programmable current limit works. Thank you!