Hello,
I would like to use the output of an LT3045 LDO (set at +5V in this case) as the upper voltage rail for a protection diode as pictured below:
At an input voltage around 5.7V (on the TRIG-SYNC In line) the diode begins to turn on (1 mA current), and at an input voltage of 6.0V the diode is at it's maximum current (200 mA).
My question is, in the broadest terms, will this work?
Particularly, how much reverse current will the LT3045 output tolerate and where does that current go?
Thank you very much for your help,
Tony