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Question about LTC7003 Bootstrapped Capacitor

Category: Datasheet/Specs
Product Number: LTC7003

Hello,

I have a question regarding the calculation of a bootstrapped capacitor, Cb.

On page 16 of the data sheet, there is the following statement.

On the other hand, the calculation formula on page 17 is as follows.

Here is my question.

Is the bootstrapped capacitor Cb required to be at least 10 times greater than Qg?

The formula on page 17 does not state 10x, which does not match the explanation on page 16, so let me check.

Best Regards,

Kazu

Parents
  • Hello Kazu,

    Is the bootstrapped capacitor Cb required to be at least 10 times greater than Qg?

    you cannot directly compare capacitance with charge.

    The formula on page 17 does not state 10x, which does not match the explanation on page 16, so let me check.

    The formula means: the voltage over the bootstrap capacitor must not fall more than 1V to completely charge the gate of the FET. As a typical voltage over the bootstrap capacitor may be in the range of 10V, you have again the factor 10.

    Please tell me the internal operation of LTC7003 when the external NMOSFET is turned off due to small bootstrapped capacitance.

    I believe it is operating as follows, is this correct?

      The reason why TG voltage drops is because bootstrapped capacitance < gate capacitance of external NMOSFET,

    When the bootstrap capacitor is too small, the voltage over the BST-capacitor will drop too much when the FET is switched. And the LTC7003 monitors this voltage and switches the ouput off, when it is too small. The datasheet says:

    "The LTC7003 additionally implements protection features
    which prohibit TGUP being pulled to BST when V IN, V CC
    or (VBST –V TS) are not within proper operating ranges."

    Just for curiosity: why are you so much interested in minimal BST-capacitance? Normally you dimension the capacitor big enough with some reserve and don't try to hit the minimum possible value. 

    best regards

    Achim

Reply
  • Hello Kazu,

    Is the bootstrapped capacitor Cb required to be at least 10 times greater than Qg?

    you cannot directly compare capacitance with charge.

    The formula on page 17 does not state 10x, which does not match the explanation on page 16, so let me check.

    The formula means: the voltage over the bootstrap capacitor must not fall more than 1V to completely charge the gate of the FET. As a typical voltage over the bootstrap capacitor may be in the range of 10V, you have again the factor 10.

    Please tell me the internal operation of LTC7003 when the external NMOSFET is turned off due to small bootstrapped capacitance.

    I believe it is operating as follows, is this correct?

      The reason why TG voltage drops is because bootstrapped capacitance < gate capacitance of external NMOSFET,

    When the bootstrap capacitor is too small, the voltage over the BST-capacitor will drop too much when the FET is switched. And the LTC7003 monitors this voltage and switches the ouput off, when it is too small. The datasheet says:

    "The LTC7003 additionally implements protection features
    which prohibit TGUP being pulled to BST when V IN, V CC
    or (VBST –V TS) are not within proper operating ranges."

    Just for curiosity: why are you so much interested in minimal BST-capacitance? Normally you dimension the capacitor big enough with some reserve and don't try to hit the minimum possible value. 

    best regards

    Achim

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