In the case of a circuit with 5V input and 1Ω load, the output is also 5V, so 5A flows.
Here, if a resistor is connected to the CLIM pin and the current limit is set to 2A, the output will be 2V since the load is 1Ω.
In this case, a voltage drop of 5V-2V=3V occurs between the input and output of the LTC4415, and the current = 2A, so LTC4415 will result in a loss of 6W.
Is the above correct?
If so, the LTC4415 will instantly activate overheat protection. Is there any way to avoid this?
Or is it wrong to use it in this way?