LT1935
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The LT1935 is the industry’s highest power SOT-23 switching regulator. Its unprecedented 2A, 40V internal switch allows high output currents to be generated...
Datasheet
LT1935 on Analog.com
Hello ADI.
I am considering the LT1935 boost DC-DC converter for a new design. My question pertains to the typical application shown on figure 1 of the data sheet. See the circuit pasted below. Vin=5V, Vout=12V @ 600mA. From the curve, efficiency=87% at 600 mA. Data sheet page 2 lists max junction temp=125C and SOT23 thermal resistance (Rja) = 113C/W. For figure 1, I calculate Pout=7.2W, and Pdis=1.08W. Assuming Tambient=22C, and Rja=113C/W, Tj=22C + 1.08W*113C/W = 144C. Since 144C > 125C, this would cause the LT1935 to fail.
My question is: Does ADI expect the PCB copper connected to the LT1935 ground pin to lower the thermal resistance down much lower than 113C/W? To be comfortable using the LT1935 at 22C with the figure 1 circuit, I would want to keep Tj=100C max. In that case, Rja=72C/W or lower. If you agree, how do I calculate PCB copper area required to achieve Rja=72C/W or lower? Thank you.

The answer to my question has been found. Not all of the 1.08W is dissipated by the LT1935 per a LTSPICE efficiency report. It turns out 0.39W is dissipated by LT1935. L1 and D1 also dissipate power. Now LT1935 Tj = 22 C + (0.39 W * 113 C/W) = 66 C. Much better.