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[LTC3871] SETCUR Voltage

Category: Hardware
Product Number: LTC3871

Hi team,

My customer is trying to set the SETCUR voltage with a resistive voltage divider by connecting a resistor not only to GND but also to a separate 3.3V supply to set the SETCUR.

However, when they actually measure the SETCUR voltage, it is much lower than the design value.

Is it not possible to use it in a resistor divider network like this?

Or does the pullup need to be 5V?

I have one more question.

They say the voltage on SETCUR is 0V at light load.

I have read the datasheet and understand that this is not the case, is this understanding correct?

Best regards,

T-yoshi

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  • FormerMember
    0 FormerMember
on Nov 16, 2022 7:02 PM

Hi T-Yoshi,

They say the voltage on SETCUR is 0V at light load.

I have read the datasheet and understand that this is not the case, is this understanding correct?

During at light load / no load, SETCUR voltage should be around 1.25V.

My customer is trying to set the SETCUR voltage with a resistive voltage divider by connecting a resistor not only to GND but also to a separate 3.3V supply to set the SETCUR.

However, when they actually measure the SETCUR voltage, it is much lower than the design value.

Is it not possible to use it in a resistor divider network like this?

SETCUR voltage divider can be connected to an input supply of 3.3V as long as it satisfies the calculations (Rsense & current limit).

I do, however, have seen during bench testing that the Vsetcur voltage is either lower or higher than expected calculation and would adjust the divider resistors accordingly.

Regards,

Jhun

  • Hi Jhun-san,

    Thank you for your response.

    As additional information, SETCUR goes to 0V at start-up and at light loads.

    When the load current increases after startup, the constant current source turns ON, and after that the constant current source keeps turning ON.

    As far as I can see from the datasheet, the constant current source is driven by V5, so I think that 7.5uA will be output immediately when V5 starts.

    Is it correct?

    Best regards,

    T-yoshi

  • FormerMember
    0 FormerMember on Nov 17, 2022 9:22 PM in reply to T_yoshi

    I think I misunderstood the question. Let me correct myself.

    What you will see on the IMON at no load/light load is 1.25V.

    When using the SETCUR with voltage divider, what you will see on the pin voltage should be the voltage drop across the low side resistor, this is also be affected by the 7.5uA sourced by the pin, regardless of the load.

    See snip below. Please make sure that the voltage divider satisfies the condition below.

    As far as I can see from the datasheet, the constant current source is driven by V5, so I think that 7.5uA will be output immediately when V5 starts.

    This is my understanding as well. 

    Regards,

    Jhun

  • Reply
    • FormerMember
      0 FormerMember
    on Nov 17, 2022 9:22 PM in reply to T_yoshi

    I think I misunderstood the question. Let me correct myself.

    What you will see on the IMON at no load/light load is 1.25V.

    When using the SETCUR with voltage divider, what you will see on the pin voltage should be the voltage drop across the low side resistor, this is also be affected by the 7.5uA sourced by the pin, regardless of the load.

    See snip below. Please make sure that the voltage divider satisfies the condition below.

    As far as I can see from the datasheet, the constant current source is driven by V5, so I think that 7.5uA will be output immediately when V5 starts.

    This is my understanding as well. 

    Regards,

    Jhun

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