LT3050 IMIN

Hello Theoderkaffee,

In the typical application, Iopen = 10mA and Vout=5V. I tried calculating using the equation provided for RImin and got the same value which is around 11.3kOhm

Regards,

Nino

Hi Nino

I used this equation. If I have 3.3V output voltage an a IMIN of 5mA I get a value for R_IMIN of more than 140 kOhm. If I remove "-36.8" from the equation I get the same value as in the example with 10 mA and 22,9k form 5 mA. So the equation seems to have an error. Or the example.

Regards

Theo

I removed -36.8*I_OPEN.

Hi,

Upon plugging the values into the equation, I see no problem with the results I'm having when compared with the typical application values.

For Imin=5mA and Vout=3.3V

_{R\text{IMIN}}=\frac{119.85-(1.68-36.8\times0.005)\times3.3}{0.005}\approx22900

For Imin=10mA and Vout=5V

_{R\text{IMIN}}=\frac{119.85-(1.68-36.8\times0.01)\times5}{0.01}\approx11300

Regards,

Nino

Ok. Now it checks out. Found my mistake.

Tanks a lot.

Regards

Theo

Ok. Now it checks out. Found my mistake.

Tanks a lot.

Regards

Theo