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ADN8835 voltages of TEMPSET vs temperature - how to calibrate

It is perhaps an unlearned question.... no, it definitely is an unlearned question......I'm scratching my codie head  :)

If I use a NTC thermistor of 10k ohms as the sensor - how can I set the temperature in terms of voltage at the TEMPSET input, and read the temperature from the TEMPOUT output?  In other words, I think the question is what is the gain I can expect from the thermistor input to the TEMPOUT output?

I am starting with the ADN8835-EVALZ evaluation board.  

Thanks in advance for your valuable time to answer.

Edit Notes

added one more statement
[edited by: tk_cybel at 11:40 AM (GMT -5) on 7 Nov 2021]
  • Hi,

    Moving this thread to Power By Linear. Someone should be able to answer your query. 


    Cheers,

    Ivan

  • Hi ,

    Thanks for reaching out.

    As for your question, it will be depending on your thermistor amplifier network component values. 
    First, you need to define the temperature you are going to maintain and the boundaries.

    The lower temp boundary will be TLOW, the target temp as TMID and the higher boundary as THIGH.
    The output of the thermistor network amplifier should swing between ~0.3V (ideally 0V) and 2.2V (ideally 2.5V).
    The curve in the datasheet figure 34 is an example with the TMID = 25degC +/- 40degC as limit.
    The step by step process in computing the values in order to obtain the curve is in the thermistor amplifier setup section of the datasheet.

    Now, the corresponding OUT1 voltage of the temperature set in the thermistor amplifier network will be the TEMPSET value.
    hope this helps. 


    Regards,
    Noel

  • It is very helpful indeed.  I did not know the useful ranges of the OUT1 amplifier, and it did not occur to me that Figure 34 was telling me.   Knowing this and the other information you provided, I'm able to see the procedure more clearly.

    I have more digging to do.  Thank you for taking your time to reply to my question.  I'm going to see where I go with this.