I am considering a circuit driven by a FET with Qg of 50nC.
In the datasheet of LTC7803, it says "The value of the boost capacitor, CB, needs to be 100 times that of the total input capacitance of the topside MOSFET.".
To drive a 50nC FET, it needs 50nC x 100 = 5000nC
I think that it means CB = Q / Vintvcc = 5000nC / 5.15V = 970nF.
Is it correct?
If the above is correct, the CB will be 1uF.
Can LTC7803 keep driving 1uF CB?
I'm worried if the boot voltage can be maintained if the switching frequency is set to 3MHz or if the Duty increases.
I would like to set the switching frequency to 2MHz or higher if possible.
I'm thinking of making 5V from a 12V battery, but I still don't know what the battery drop will be.
I would like to know the restrictions on whether the bootstrap can be retained even if it drops to 7V.