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LT1764A in parallel

I want to use dual LT1764A plus half LT1366 to create 6A per rail linear power supply.  There is not enough detailed information on how "Paralleling of Regulators for Higher Output Current' can be applied.  

Questions:

  • Are the 0.01 ohm R1 and R2 resistors represent the pcb trace resistance?  Or they are real resistors?
  • What if both LT1764A are the adjustable version?  How will the implementation be different?
  • Other than voltage dividers R6 and R7, for the other resistors (R3, R4, R5), will the values be different for different output voltages?
  • What are the wattage requirement of resistors other than R6 & R7?

I am building linear PSU for a low-powered mini-ITX motherboard (10W TDP Pentium Silver).  Here are the requirement based on initial tests:

  • 12V 3A
  • 5VSB 3A
  • 5V 6A
  • 3.3V 6A

Dual LT1764A will be required for the 5V and 3.3V ATX PSU rails.

Thank you in advance for your help. 

  • Page 24 of Application Note 98 explains how a circuit works that is similar to the circuit that you show in your post, except the circuit in AN98 senses the output current instead of the input current to the LDOs.  I show the applicable excerpt from AN98 in the image below:

    AN98 p24_1.png

  • Thank you ARad.  After I posted the above question and not seeing any replies, I wrote to AD again and received email replies from the regional technical support based in Singapore.  They provided the implementation details not available in LT1764A datasheet. 

    The LT108x series can be paralleled without using op amp, just ballast resistors.  However, for parallel LT1764A, op amp is required.  I have purchased the components and will try.  The 0.01 ohm resistors are expensive.