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Output capacitor for LT8602

nick11 on May 11, 2018

Hi all.

From the LT8602 datasheet, pag. 19, I saw that the output capacitor should be: Cout>10*L*(Ilim/Vout)^2.

For channel 3 and 4, is the Ilim(TYP) = 3.1A? (In the datasheet pg. 4-5 I saw SWx Average current limit between 1.8-3.5A).

If so, with Vout=1V (for channel #4) and L=1.5uH, Cout should be: Cout>144uF. Is it correct?

Thank you.

Nicola

JoshYe

on May 22, 2018 3:52 AM over 2 years ago
Hi Nicola,

The equation is right, and it is for 5% overshoot. If you do not need such small overshoot, the cap can be smaller. Also a 1uH or smaller inductor is usually good for 1V output. The schematic in the datasheet gives reasonable values, and provides a start point for your real applications.
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nick11 on May 22, 2018 11:27 AM over 2 years ago

Thank you for the answer.

My question was asked to verify that the values in the formula are correct.

Regards, Nicola
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