Post Go back to editing

TIA LTC6268-10 input overdrive - this is bad?

Hello everybody! I'm developing an optical receiver based on an avalanche photodiode. As a transimpedance amplifier I want to use the LTC6268-10 chip. The power range of the signal I receive is quite large, from 40 nA to 15 mA. The planned transimpedance is 400 kOhm. This will provide an acceptable bandwidth with a good gain of 40 nA signal. But the next question arises. What will happen with LTC6268-10 in cases where the input is overdriven and the output is overloaded? At currents of tens of μA at the input of TIA, the spice model LTC6268-10 goes into saturation. How will the real chip behave? Will not it break down? Is it necessary to somehow deal with the overdrive of the input or I can leave everything as is? I'm only interested in the leading edge of the signal, so that the extension of the signal at the output is not a problem for me.

attachments.zip
  • Hi,

    With a signal range of 40 nA to 15 mA and a feedback resistor of 402k, will surely saturate the amplifier at the maximum current (15 mA).  15 mA current flowing into 402k resistor will raise the inverting voltage to 15 mA * 402 kohms = 6.03 kV and will most like destroy the amplifier. At saturation, the output of the amplifier will not measure the input current and is therefore useless. Recovery from such overload takes time, which depends on the sensor capacitance and the feedback resistor, τ = RC. The amplifier remains some sort of "useless" mode during the overload recovery.

     

    Since you said that the anticipated max current would be 15 mA, why not design the feedback resistor based on 15 mA? So let's assume a supply of 5V, choose RF = 5V/0.015 = 300 ohms. Although it sacrifices the sensitivity for your TIA, this is a workable solution.  RF=402kohm is not a realistic workable solution.

     

    Regards,

    Jino

  • Hi, Jino
    The fact is that the sensitivity of the TIA is very important for me. I'm going to do the maximum possible amplification that the frequency band will allow me. The theory says that the greater the gain on the TIA, the higher the signal-to-noise ratio, and this is also important for me. I understand the problem with the huge voltage at the input of the TIA in the case of a current of 15 mA. In reality, there will not be such voltage, because the signal source is real and has certain limits. However, the voltage at the input of LTC6268-10 can become unacceptably high, I admit that this can happen. Actually, I'm racking my brains to solve this problem. Two questions interest me: how will the LTC6268-10 behave in case of saturation of the output, and how to secure the chip from large input signals?

    Regards,

    Mikalay


  • Hi Mikalay,

    Ref:Working with Avalanche photo diode - Beginner problems 

    i am now not using a LTC6268-10 as i am facing the stability issues, i am trying to use a LTC6268 rather, even that also when saturates has the problem of positive overshoot pulse in output

    after debugging further i found that the photo diode i am using is so responsive that it generates a current of 50mA

    so an input current of 50mA makes it to saturate and behave abnormally, so i am using a diode at the input PMEG4002EJ which can bypass the extra current and solves the problem to an extent only, this is happening as because i am feeding toomuch current to the opamp

    for now placing a diode in the input is the only workarround i have done

  • are you able to achieve the 40nA target ?? its seems like a night mare to me