Hi,

"The two 100 Ω resistors and the 1 μF capacitor form a differential filter with a cutoff frequency of 800 Hz. The two 0.01 μF capacitors form common-mode filters with a cutoff frequency of 160 kHz."

Please can you provide the equations to get both cutoff frequencies ?

Thanks,

The equation to determine the cutoff frequency of the different filter created by the two 100Ω resistors and the 1μF capacitor is

1 / (2 * pi * R * C) or 1 / (2 * 3.14159 * 100 * 1e-6) = 1592 Hz

This is then divided by 2 since it is shared between the two inputs resulting in 796 Hz

The equation for the common-mode filter is exactly the same, except the value is not divided by two since the filter is not shared between the two inputs.

1 / (2 * 3.14159 * 100 * 0.01e-6) = 159,155 Hz