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ADXL1005 output stability vs. eval-board RC filter

Thread Summary

The user is seeking a stability check for the ADXL1005 accelerometer's output when driving capacitive loads through series resistors. The final answer suggests a minimum series resistance of 500 ohms for capacitive loads over 100 pF. The accompanying answer indicates a detailed response will be provided later, but the core solution is to ensure the series resistance is at least 500 ohms to maintain stability.
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Category: Datasheet/Specs
Product Number: ADXL1005

I’m experimenting with an ADXL1005 accelerometer (ADXL1005 (Rev. 0)) and trying to reconcile its output-load stability note with the EVAL-ADXL1005Z schematic filter.

Datasheet rule:

  • “Output amplifier is stable while driving capacitive loads up to 100 pF directly (no series resistor).”

  • “For capacitive loads > 100 pF, add a series resistor ≥ 8 kΩ.”

  • Output capacitance must not exceed 22 nF.”

Eval board filter:

Vout ── R1 ──●── R2 ──●──> to rest of chain
             │        │
            C1       C2
             │        │
            GND      GND

With R1 = 487 ΩR2 = 976 ΩC1 = C2 = 3.9 nF.

So there are caps on the order of nF, but they're behind resistors, not tied directly to Vout.

So what I understand (and where I'm stuck)

For a single branch of the filter:

The equivalent capacitance at ω:
Ceq​(ω)​=C / (1+(ωCR_s​)^2)

Load angle ∠Z = -arctan(1/(ωCR_2))

I can then compute Ceq and load angle:
At 70kHz (close to the datasheet's small-signal output bandwidth)
Ceq = 1.65 nF and ∠Z = -29°

So C_eq is much larger than 100pF, but the phase angle is far from -90° because the series resistors add a substantial real part. This seems to be why the eval network is stable in practice. (Maybe?)

Q1 (Main): The datasheet’s 100 pF rule is clearly for a capacitor physically tied to Vout. When caps sit behind hundreds of ohms (like R1/R2 above), what is the recommended stability check on the load as “seen” at the pin?

  • Is a criterion like “∠Z > -45°" at some check frequency fcf_cfc​ (say 70–100 kHz) a reasonable rule of thumb?

Q2 (Finding the “break point”):
Thought experiment: let R1 → 0 Ω with the filter above. By the Intermediate Value Theorem, there must be some R1 where the load becomes “too capacitive” and stability is lost.
How do I compute that boundary from the datasheet info?

Does anyone have a better phase-margin-aware criterion ADI would implicitly be using?