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ADN4695 Differential Output Voltage Magnitude



		

			

									
						Terumasa
					
							

			
				
									
											
							 		
		        	            							
			
			    	
			                    
                
				                on May 22, 2018 
				
			
			
		


				
		

		    		    
		    
		    	
			
Hello

 
Our customer will use ADN4695 and evaluates this.

 
Then , the measured  differential output voltage of driver is about 1.6Vpeak to peak (Y-Z) at 50ohm load (  using two  100 ohm termination).

 
The customer asks us if  value of 1.6Vpeak to peak is abnormal value 

 
because  datasheet table2 specification says that |VOD| is 480mV~ 650mV.

 
Does   |VOD|   mean  absolute valute of Y-Z voltage ?

 
Datasheet P10 figure 16 Figure 16　” ADN4690E Driver Output Eye Pattern”  describes  that |A-B| is ~1.2V and　this value is not 480mV~650mV.

 
Please let me know your advice what |VOD|  means and 

 
please let me know your adviceif the differential output voltage of 1.6Vpeak to peak. is abnormal.

 
Regards,

 
Terumasa

								


				
				
		

			
						
									
									
						
						
			
			
			
			
		


					

			





	

		
	











	

	

					



			


				
	









	
    
	

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                                 Analog Employees 
                                
                            
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                on May 22, 2018 2:43 PM
            
            
					
    
	
    

		
		
    
					
    Hi Terumasa-san,
    
 
    Yes, |Vod| means the absolute value of Y-Z. So 650mV means either +650 mV, or -650 mV for the extreme of Y-Z (i.e. the peak-to-peak will be 1.3V). The typical performance characteristic, Figure 16 in the datasheet that you mention, has |Vod| of ~530 mV, or 1.06V peak to peak output swing.
    
 
    1.6 V peak to peak seems high. Could you post an oscilloscope plot of the output waveform, and a schematic or photo of the board being used for the testing? Alternatively please send a PM if the customer doesn't wish to post the information on here.
    
 
    It seems like the output load would need to be somehow not as much a load as 50 Ohm, or else the measurement is including ringing or something to cause the larger voltage to be measured.
    
 
    Regards,
    
 
    Conal
    
			
    

		
		
		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
				
						
						
				
				
		
		
    
			
		
    
	
    

    

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                on May 23, 2018 9:42 AM
            
            
					
    
	
    

		
		
    
					
    Hello Conal,
    
 
    Thank you for your answer.
    
 
    I would like to send a E-mail with waveform and circuit desing.
    
 
     Could you teach me your E-mail address ?
    
 
    Regards,
    
 
    Terumasa
    
			
    

		
		
		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
						
				
						
				
				
		
		
    
			
		
    
	
    

    

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                on May 25, 2018 9:44 AM
            
            
					
    
	
    

		
		
    
					
    Hello Conal,
    
 
    I would like to send E-mail from below message but I do not your E-mail address .
    
 
    "please send a PM if the customer doesn't wish to post the information on here"
    
 
    Please let me know your E-mail address.
    
 
    Regards,
    
 
    Terumasa
    
			
    

		
		
		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
						
				
						
				
				
		
		
    
			
		
    
	
    

    

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                on May 28, 2018 4:06 AM
            
            
					
    
	
    

		
		
    
					
    I close this thread because I ask Conal by e-mail
    
			
    

		
		
		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
						
				
						
				
				
		
		
    
			
		
    
	
    

    

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