Our customer will use ADM3053 and ask minimum combined impedance and drive capability.
I think below. ( in the case of cable loss =0)
Is my understanding correct ?
Datasheet P.1 says "Connect 110 or more nodes on the bus".
If load of CAN bus is compesed of 110 nodes of ADM3054 in parallel ( 20Kohm minimum Differential Input Resistance of ADM2053),
Combined resistor is 180 ohm.
When this 180ohm is in parallele with !20 ohm termination resistor*2 on the CAN bus, final combined resistor is 45 ohm.
So, minimum impedance will be 45 ohm and drive capability is driver output voltage(MAX) /combined resistor = 3.0V/45 ohm =67mA.
If there is any wrong with my understanding, please let me know your advice.