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KCC Quizzes AQQ303 about the radius of a circle

1. Quote of the month: "When I die, I want to die like my grandfather who died peacefully in his sleep. Not screaming like all the passengers in his car" - Will Rogers

2. Quiz AQQ304 about finding the radius of a circle

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  • Flip the quarter circle into a semi-circle. This creates two isosceles triangles with base1=42 and base2 equal to 16. Their vertices are at the point O.  All the 4 sides equal the radius R. The difference of the heights is BC or 15. The equation for this difference is:

    15 = sqrt(R2 – 64) – sqrt(R2 – 441)

    Solving the above gives R ~ 21.60257

  • Tantalizing explanation, retiredEE.  Would you mind attaching a drawing to help me understand?

  • When I first looked at this quiz I wondered if there was a way to represent it in such a way as to use defined formulas rather than doing an analysis using the right triangle relationships. By mirroring the image, you can create two isosceles triangles as shown below.

    h = height

    a = sides = R

    b = base = 42 for ΔOD’C’CDO and 16 for ΔOB’BO

    We don’t need each height only their difference which equals 15. This gave an f(R) which I submitted to an online equation solver to calculate R.

     

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  • When I first looked at this quiz I wondered if there was a way to represent it in such a way as to use defined formulas rather than doing an analysis using the right triangle relationships. By mirroring the image, you can create two isosceles triangles as shown below.

    h = height

    a = sides = R

    b = base = 42 for ΔOD’C’CDO and 16 for ΔOB’BO

    We don’t need each height only their difference which equals 15. This gave an f(R) which I submitted to an online equation solver to calculate R.

     

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