KCC's Quizzes AQQ296 about repairing an equation in a digital display

If we assume that the dot matrix display is not a Standard 64 ASCII 5 x 7 character set (which won't allow a meaningful change to any displayed character with deletion of two dots) and assume binary then one solution is to convert two 1's to bitwise NOT, !.

If a 1 is  .  it becomes !  .  by removing a single dot in the fourth row.
             .                        .
             .                        .
             .
             .                        .

We can remove two dots converting two 1's to !.  So the equation becomes:  (!0+1) * (10-1) = !01  which is an equality.




 

If we assume that the dot matrix display is not a Standard 64 ASCII 5 x 7 character set (which won't allow a meaningful change to any displayed character with deletion of two dots) and assume binary then one solution is to convert two 1's to bitwise NOT, !.

If a 1 is  .  it becomes !  .  by removing a single dot in the fourth row.
             .                        .
             .                        .
             .
             .                        .

We can remove two dots converting two 1's to !.  So the equation becomes:  (!0+1) * (10-1) = !01  which is an equality.




 

Thanks botha ; Nice proposal, but will have then to neglect the ! sign on the right part of the equation....